Volume of a Cone

Geometry & Measurement

The volume of a cone is one-third times $\pi$ times the radius squared times the height.

Formula

V = \frac{1}{3}\pi r^2 h
Visualization

Definition

The volume of a cone with base radius $r$ and perpendicular height $h$ is $V = (1/3)\pi r^2 h$, exactly one-third of the cylinder $V = \pi r^2 h$ with the same base and height, since the cross-sectional area decreases linearly from base to apex. Doubling only the height doubles the volume, while doubling only the radius quadruples it. As an integral, $$V = \int_0^h \pi \left(\frac{rz}{h}\right)^2 dz = \frac{\pi r^2}{h^2} \cdot \frac{h^3}{3} = \frac{1}{3}\pi r^2 h,$$ where the cross-section at height $z$ is a disk of radius $r(z/h)$, scaling linearly from $0$ at the apex to $r$ at the base; the same formula holds for an oblique cone, with $h$ the perpendicular height from apex to base plane, by Cavalieri's principle.

Example

An ice cream cone with radius $4$ cm and height $9$ cm has $V = (1/3) \times \pi \times 16 \times 9 = 48\pi = 150.8$ cm$^3$. A volcano modeled as a cone with base radius $5$ km and height $3$ km has $V = (1/3)\pi \cdot 25 \cdot 3 = 25\pi = 78.5$ km$^3$. For an oblique cone, the same formula applies with $h$ as the perpendicular height, since each horizontal cross-section has the same area as in the right cone at the same height.

Key Insight

Fill a cone with water, then pour it into a cylinder with the same radius and height: you need exactly $3$ cones to fill the cylinder, which is where the $1/3$ in the formula comes from. This factor is equivalent to integrating $x^2$ from $0$ to $1$, which gives $1/3$; every shape that tapers to a point (pyramids and cones) has this same $1/3$ factor, a universal consequence of how cross-sectional area scales with the square of the distance from the apex.