Vertex of a Parabola
The vertex of a parabola is its highest or lowest point, located at the coordinates (-b/(2a), f(-b/(2a))) for a quadratic in standard form.
Formula
x = \frac{-b}{2a}
Definition
The vertex of a parabola is its turning point: the topmost point if the parabola opens downward, or the bottommost point if it opens upward, the single highest or lowest value on the graph. For a quadratic in standard form $y = ax^2 + bx + c$, the vertex's x-coordinate is $x = \frac{-b}{2a}$ (substitute back for the y-coordinate), while in vertex form $y = a(x-h)^2 + k$, the vertex is directly $(h, k)$; it is a minimum when $a > 0$ and a maximum when $a < 0$. Formally, the vertex is the unique critical point of $f(x) = ax^2 + bx + c$: setting $f'(x) = 2ax + b = 0$ gives $x = -b/(2a)$, and since $f$ is strictly convex or concave, this critical point is a global minimum or maximum, with $k$ in vertex form representing that optimal value.
Example
For $y = x^2 - 4x + 3$, the vertex is at $x = -(-4)/(2 \cdot 1) = 2$, and $y = 4 - 8 + 3 = -1$, so the vertex $(2, -1)$ is the lowest point of this upward-opening parabola. For $y = -2x^2 + 8x - 5$, $x_{\text{vertex}} = 2$ and $y_{\text{vertex}} = -8 + 16 - 5 = 3$, a maximum since $a = -2 < 0$. To minimize a cost function $C(x) = 0.5x^2 - 10x + 60$, $x_{\text{vertex}} = 10$ and $C(10) = 10$, the minimum cost.
Key Insight
The vertex is where the parabola changes direction, the minimum of an upward parabola or the maximum of a downward one, and it always sits on the axis of symmetry. Finding it is equivalent to solving an optimization problem: the vertex formula is a special case of setting the gradient to zero, the general technique used throughout multivariable calculus for unconstrained optimization.